Code Chef snackdown qualifier 1-B Solution

1.Problem: SNCKYEAR Solution

list = [2010,2015,2016,2017,2019]

T = int(input())

list_2 = []

for i in range(0,T):

    list_2.append(int(input()))

for item in list_2:

    if item in list:

        print("HOSTED")

    else:

        print("NOT HOSTED")

This Code is written in python 3.6

    

2.Problem: CHFAR Solution

T = int(input())

result =[]

while(T>0):

    data_input = input()

    list_1=list(data_input.split())

    list_1 = [int(i) for i in list_1]

    K = list_1[1]

    data_input_2 = input()

    list_2 = list(data_input_2.split())

    list_2 = [int(i) for i in list_2]

    count = 0

    for item in list_2:

        if item!=1:

            count = count+1

    if count<=K:

        result.append("YES")

    else:

        result.append("NO")

    T=T-1

for item in result:

    print(item)